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Sunday, October 27, 2013

SV#4: Unit I Concept 2: Graphing logarithmic functions and identifying x-intercepts, y-intercepts, asymptote, domain, range


The viewer needs to pay attention to how the asymptote is found. For this function, x=h, so you need to look for h to find the asymptote. The viewer must also pay attention to how to do the change of base formula to find the y- intercept. The viewer must know how to put these numbers into the calculator. To find the x-intercept, the viewer must know how to exponentiate. Also, they must pick key points that are to the right of the asymptote. Another thing to pay attention to is that the range is always all real numbers and the domain depends on the asymptote.

SP#3: Unit I Concept 1: Graphing exponential functions and identifying x-intercept, y-intercept, asymptotes, domain, and range

The viewer needs to pay special attention to the a. The a tells you if it is above or below. The viewer must also pay atention to the k because that is the asymptote. The viewer must pay attention to y=k, meaning that there are no x-value restrictions, so the domain is all real numbers. Also, the viewer must pay attention to the asymptote because the range depends on that. Another thing is that the viewer must pay attention and understand why there is no x-intercept.

Sunday, October 20, 2013

SV#3: Unit H Concept 7: Finding logs with given approximations



The viewer needs to pay special attention to a couple of things. The viewer should pay attention to the clues given to them because this can make them solve the problem faster. It can be solved faster because many times, the numbers you can simplify with are given. The viewer must also pay attention to the base because the base can possibly give them clues. The viewer must also pay attention to the letters given in the clues. These letters are the last step to the problem, so they are very important.

Monday, October 7, 2013

SV #2: Unit G Concept #1-7: Rational Functions


This problem shows you how to find a rational function when the degree on top is bigger than the degree on bottom. This means that it is a slant asymptote and this means that there is no horizontal asymptote. This problem consists of various steps that are all explained in the video above. To graph this, we must find the x and y intercepts, the domain, and a couple of points to help us plot our lines into the graph. This example contains a numerator with a degree of three, a denominator with a degree of two, one vertical asymptote, one hole, and two x-intercepts.

In this problem, we must focus on the degrees of the beginning of the problem. This is important because this tells us what asymptote it is. When there is a slant asymptote, there is no horizontal assymptote and when there is a horizontal, there is no slant. To find a slant asymptote, we need to use long division. The remainder does not matter in this case. The equation you get is for the line that goes on the graph. The viewer must also pay close attention to finding the correct vertical asymptote. If it is done correctly, then it makes you a step closer in having a correct graph. The viewer must also pay attention to the holes the problem has. The viewer must plot points correctly on the graph (x/y inercepts., holes).